A ball is dropped from a height of 122.5 m , how long it take the ball to reach the ground if acceleration is 9.8m/s2
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Answer:
the needed time maybe 5s
Explanation:
we know that h= it+1/2 at^2
;122.5=0×t+1/2×9.8t^2
;122.5=4.9t^2
;t is maybe 5s
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