a ball is dropped from a height of 144 m and it rebounds to two thirds of the height from which it falls. if it continues to rebound, what distance will the ball have travelled before coming to rest?
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Distance traveled first time+2×{a÷(1-r)}
Where a=96 and r=2/3
=144+2{96÷(1–2/3)}
=144+2{96÷(1/3)}
=144+2{96×3}
=144+2×288
=144+576
=720
So the final answer for this question is 720.
If there is any confusion please leave a comment below.
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