Question

A ball is dropped from a height of 20 m above the ground. The ratio of its kinetic energy to potential energy when it is at a height of 8 m from ground
(a) 4:3 (b) 3:1 (c) 1:3 (d) 3:4

Pls tell the answer
I want the solution (complete)
Whosoever gives the answer with solution will be marked brainliest

Answer 1

Answer:

3:1

Explanation:

Total Mechanical energy = k.E + Potential energy

when is at heights 20 m it's total mechanical energy is equal to potential energy

when the ball is 8m from the ground (some potential energy get converted into change in kinetic energy)

so

velocity gained when it's reaches 8 m from the ground

V = ✓2gh ( by using v^2 = u^2 +2as)

v =✓2×10×12

ratio of K.E/ U

1/2 mv^2/ mgh

v^2/ 2gh

240/80

3:1

Answer 2

A ball is dropped from a height of 20 m above the ground. The ratio of its kinetic energy to potential energy when it is at a height of 8 m from ground (a) 4:3 (b) 3:1 (c) 1:3 (d) 3:4

Ans:-

240:80

Ans:- 3.1

Thanks,

emptyz (anonymous)