Question

a ball is dropped from a height of 20m if its velocity increases uniformly at the rate of 10ms^2 with what velocity will it strike the ground? ​

Answer 1

Answer:

20m/s

Step-by-step explanation:

given

u=0m/s

v=?

h=20m

a=10m/s²

we know

V²=U²+2as

V²= 0+ 2 x 10m/s²x 20m

V²-0=400m²/s²

V²= 400m²/s²

V= 20m/s

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Answer 2

Answer :

➥ The final velocity of a ball = 20 m/s

Given :

➤ Distance from a ball is dropped = 20 m

➤ Acceleration of a ball = 10 m/s²

To Find :

➤ Final velocity of a ball = ?

Required Solution :

For solving this question, let's first know about final velocity.

The last velocity of an object after a period of time is called final velocity.

• Final velocity is a vector quantity.

• Final velocity measures the speed and direction of a moving body.

• The SI unit of final velocity is m/s.

• Final velocity is represented by v.

❒ According to given question, given that a ball is dropped from a height of 20 m so, I Initial velocity is 0 m/s because the ball is is dropped, Distance or height from a ball is height is 20 m/s acceleration of a ball is 10 m/s.

Now, we have Intial velocity, Distance, and Acceleration of a ball.

• Initial velocity of a ball = 0 m/s
• Distance from a ball is dropped = 20m
• Acceleration of a ball = 10 m/s²

We can find final velocity of a ball by using the third equation of motion which says v² = u² + 2as.

Here,

• v is the Final velocity in m/s.
• u is the Initial velocity in m/s.
• a is the Acceleration in m/s².
• s is the Distance in m.

✎ So let's find Final velocity (v) !

⇛ v² = u² + 2as

⇛ v² = 0² + 2 × 10 × 20

⇛ v² = 0 + 2 × 10 × 20

⇛ v² = 0 + 20 × 20

⇛ v² = 0 + 400

⇛ v² = 400

⇛ v = √400

⇛ v = 20 m/s

║Hence, the final velocity of a ball is 20 m/s.║

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Some related equations :

⪼ First equation of motion: v = u + at

⪼ Second equation of motion: s = ut + ½ at²

⪼ Third equation of motion: v² = u² + 2as

Where,

• v is the final velocity in m/s.
• u is the intial velocity in m/s.
• a is the acceleration in m/s².
• t is the time taken second.
• s is the distance in m.

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