A ball is dropped from a height of 20m. its velocity increases uniformly at the rate of 10m/s^2. with what velocity will it strike the ground? and after what time?
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Explanation:
Answer is 20m/s
solution is in the attached pic ...
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Answer:
the explanation is given below
Explanation:
AS given in the picture below -
d = 20m
initial velocity (u) = 0
Final velocity (v) = ?
Acceleration = 10m/s²
3rd equation of motion ;
2as =v² -u²
so, 2× 10×20 = v² - 0²
400 = v²
v= √400
=20m/s
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