A ball is dropped from a height of 30 m .If its velocity increases uniformly at the rate of 10m/s2,the velocity with which they strike the ground is -
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Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’.
Given things :-
Initial Velocity of the ball (u) = 0
Distance or height of fall (s) = 20 m
Downward acceleration (a) = 10 m s-2
As we know
2as = v² – u²
v²= 2as + u²
v² = (2 x 10 x 20 ) + 0
v² = 400
Final velocity of ball (v) = 20 ms-1
t = (v – u)/a
Time taken by the ball to strike (t) = (20 – 0)/10
t = 20/10
t = 2 seconds
The final velocity with which ball will strike the ground is (v) = 20 ms-1
The time it takes to strike the ground (t) = 2 seconds
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