Question

A ball is dropped from a height of 39.2 M calculate the final velocity just before hit the ground

Answer 1

$v^{2}- u^{2} = 2as$

s is the height = 39.2m

g = a= 9.8m/$s^{2}$

initial velocity is 0

$v^{2}$ = 2(9.8)(39.2)

$v^{2} = 768.32$

$v = 27.7m/s (approx)$