a ball is dropped from a height of 48m.after striking the ground , it rebounds to three-fifths the height it dropped from, and so on for successive rebound. what is the total distance travelledby the ball until it comes to rest?
Answers
Answered by
1
Answer:
Step-by-step explanation:
Y(total)= (48m)+2[(48m x 3) +(48m x (3)^2) + (48m x (3)^3) + ...].
Recall the sum to infinity of an exponential sequence S = a/1-r for |r|< 1 which very well fits our problem for which r= 3 and a= 48m x 3 =144m.
S = 144/(1-(3)) =144/(1/2) =144 x2=288m.
Total distance Y(total) then becomes
(48m) + [288m] = 336m.
Similar questions