A ball is dropped from a height of 72 feet and bounces 2/3 of the previous height. What would be the total distance traveled by the ball: after the 5th bounce? (Hint: after the 5th bounce means before the 6th bounce)before coming to rest? *
Answers
Answer:
672 feet
Step-by-step explanation:
Each drop is 72 feet and each bounce is 48 feet. The bounce is 48 feet because that is 2/3 of 72 feet. To get 48 feet you need to multiply 72 times 2/3. Since the ball is being dropped and bouncing 5 times, you need to multiply the dropping height (72 feet) times 5, which would be equal to 360. Now you multiply the height after each bounce (48 feet) times 5, which is 240. Next you would need to add 360 plus 240 to get the total number of feet of the height of the ball from when it was dropped and when it was bounced. The total would be 600. The last step is to add 72 because we need to find the total distance traveled by the ball which means that after the 5th bounce, the ball still went another 72 feet and stopped right before bouncing again. 600 plus 72 is 672, and that's the final answer.