A ball is dropped from a height of 90m. How long it will take to reach the ground
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Answer:
4.242 sec
Step-by-step explanation:
S = ut +( 1/2)at^2
S = 90 m
u = 0 as dropped
a = g
90 = (1/2) g t^2
t^2 = 180/g
taking g = 10m/s^2
t^2 = 180/10 = 18
t = 3 root2
t = 3*1.414
t = 4.242 sec
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