Question

a ball is dropped from a height of200m after 5 sec how much velocity and th height from the ground​

Answer 1

Answer:

Height from the ground after 5 seconds is 77.5 m

Velocity after 5 seconds is 49m/s

Explanation:

Initial height = 200m

Distance travelled by the ball after 5 seconds,

                     $S=ut+\frac{1}{2}at^2$

                     Initial velocity, u = 0 m/s

                     acceleration due to gravity, a = g= 9.8 $m/s^{2}$

                     time , t = 5 s

                 ⇒

                    $\begin{aligned}S=\frac{1}{2}gt^2=\frac{1}{2}\times 9\cdot 8\times 5^2\\=122.5m\end{aligned}$

Therefore, Height from the ground after 5 seconds = 200 - 122.5 = 77.5 m

Velocity after 5 seconds = v = u +at = gt = 9.8 $\times$ 5 = 49 m/s