Question

a ball is dropped from a heighy of 20 m a second ball is thrown downward from the same height after one second with initial velocity u .if both the balls reach the ground at the sane time calculate the initial velocity of the second ball

Answer 1

here we use formula for 2nd ball

v2=u2+2as
v=0
-u2= 2as
=2*9.8*20
=392
u= √392
= 19.7( approx)

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