Question

a ball is dropped from a high rise platform at t=o starting from rest. after 6 seconds another ball is thrown downwards from the same platform with speed v . the two ball meet at t=18s. what is the value of v ?(take g =10m/s²)

Answer 1

HERE IS YOURS ANSWER;

◆ Distance between the two balls after 6 secs = ½ * 10 * 62 = 180

◆ Relative velocity of second ball(wrt first ball) so that it can cover this distance = 180/ 12 = 15m/s

 
◆ Velocity of first ball (at t= 6) =  10* 6 = 60

 v= 60 + 15 =75m/s

★ So, the value of v is 75 M/S ★


HOPE IT HELPS

Answer 2

sorry I didn't get the ans