Question

a ball is dropped from a high tower it covers 36% of its total journey in the last second find the height of tower
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Answer 1

Answer:

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Let H be the height of the building and t be the time to fall through the height H.

Then,

$</em></strong><strong><em>H</em></strong><strong><em> = \frac{1}{2} g {t}^{2}$

$= 5 {t}^{2} .........(1)$

In (t-1) second, the distance travelled is 1-0.36

=> 0.64= H

$0.64h = 5( {t - 1})^{2} ..........(2)$

$\frac{(2)}{(1)} gives \: 0.64 = \frac{( {t - 1})^{2} }{ {t}^{2} }$

$or \: 0.8 = \frac{(t - 1)}{t}$

Solving we get, t= 5 sec.

Using (1) we get H = 125m.

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