a ball is dropped from a particular height then the ratio of distance covered by ball in 5th and 3rd second is
5:9
5:3
9:5
3:5
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Answer:
Distance covered in nth second,
∝n
2
−(n−1)
2
∝n
2
−[n
2
+1−2n]
∝2n−1
n=2→2(2)−1=3
n=3→2(3)−1=5
n=5→2(5)−1=9
3:5:9l
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