a ball is dropped from a tall bridge of height 81 m. What will the speed of the ball be immediately before it hits the ground, in units of m/s?
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Answer:
approximately 40
Explanation:
x=ut+1/2at^²
81=0+5t^²
t=√81/5
t=4(approximately)
v=u+ at
v=0+10(4)
v= 40
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