A ball is dropped from a top of a tower of 100 m height. Simultaneously another ball was thrown upward from bottom of the tower with a speed
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Secondary SchoolPhysics 5 points
A ball is dropped from the top of a tower 100m high. Simultaneously another ball is thrown upward with a speed of 50m/s. after what time do they cross each other
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⇒ the time taken by both balls at point P has same time ' t ' seconds .
⇒ for first ball , that is in the diagram from A to P
S = ut + 1/2 at²
we know that u = 0 and a = g
⇒ ( 100 - x ) = (0)t + 1/2 gt²------------(1)
now, for the second ball from B to P in the diagram ,
S = u't + 1/2 at²
where u = 50 m/s and a = -g
therefore, x = 50(t) - 1/2gt² ------------------(2)
by adding equation (1) and (2) we will get ,
100 = 50 t
implies, t = 100 / 50
therefore t = 2 sec .
therefore the time that they cross each other is 2 seconds.