Question

A ball is dropped from a tower height h.The time taken by the ball to reach the ground is T.Find the position of the ball at Ts/3

Answer 1

Answer: 5T^2/9

Explanation: Given: u=0m/s( because the ball is at rest when it is thrown)

g=10m/s^2(because the gravity is acting on it)

h=H m

t= T/3 s

Proof: using the second equation of newton

h=ut+1/2gt^2

Putting the values

H=(0)*T/3+1/2*10*(T/3) ^2

H=5*T^2/9

H=position of the ball during the giventime