a ball is dropped from a tower.in the last second of its motion it travels a distance of 15m . find height of tower
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Sorry I don't know ♀️
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V= U + gt
V=final velocity=?
U=Initial velocity=0
g= acceleration due to gravity=9.8 m/s^2
t= Time=1
V=U + gt
V=0+9.8×1
V=9.8 m/s
In 1 second the ball travels=15 m.
Speed of the ball=15m/s
The rate of accleration from 0 to 9.7 takes a total of 9.7 seconds. So height of the tower = 15×9.7= 145.5 m
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