Question

A ball is dropped from a tower. In the last second of its motion it travels a distance of 15 m. Find the
height of the tower. [Take g = 10m/sec^2]
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Answer 1

Answer:

Let height of tower is h.

Time take to reach at ground =t

h=1/2g t^2

t=sqrt2h/g

Now,as in last second it travels 15m

h-15=1/2g(t-1)^2

Put value of t from above and solve for h

h=20m