Question

A ball is dropped from a tower of height 125 m. If g = 10 ms-2, find the time taken by it to reach the ground?​

please give steps as well​

Answer 1

Answer:

____________________

GIVEN:

HEIGHT- 125m

g - 10m/s^2

initial velocity -0

time- ?

using second equation of motion-

h=ut+ 1/2gt^2

125= 0*t+1/2*10*t^2

125= 0+1/2*10*t^2

125= 5*t^2

125/5=t^2

t^2= 25

t=5 sec

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Answer 2

${ \red{ \underline{ \underline{ \huge{ \mathfrak{given}}}}}}$

distance (s) = 125m

initial velocity (u) = 0

acceleration(a) = 10 ms-2

${ \red{ \underline{ \huge{ \mathfrak{to \: find}}}}}$

${ \huge{time}}$

${ \red { \underline{ \huge{ \mathfrak{formula}}}}}$

${ \huge{s \: = ut \frac{1}{2} {at}^{2}}}$

${ \red{ \underline{ \huge{ \mathfrak{solution}}}}}$

125 = 0 t + 1/2 (10 t²)

125 = 5 t²

25 = t²

taking square root

t = 5

${ \red { \underline{ \huge{ \mathfrak{answer}}}}}$

${ \huge{5}}$

${ \green{ \underline{ \huge{ \mathcal{be \: brainly}}}}}$