Question

A ball is dropped from a tower of height 30.0 m. If the terminal speed of the ball is 25.0

Answer 1

Answer:

c 2.47

Explanation:

PART 1

Terminal speed is the maximum speed of a body or the final speed of body.

Here, we will need to find time taken by body to attain terminal speed,

v=u+at

25=0+10t

therefore,t=2.5 sec

Now, Height lost in 2.5 sec;

S=ut+1/2at^2

S=1/2*10*2.5*2.5

S=31.25

PART 2

Here Height lost is grater than height of tower so, it will hit ground before attaining terminal velocity.

hence,

by using S=ut+1/2at^2;

30=1/2*10*t^2

hence

t^2=6

t=2.47

only one option is less than 2.5 so without solving part 2 we get ans.

Thank you