Question

a ball is dropped from a tower of height 5m. with what velocity does it strike the ground (g= 10 m/s)​

Answer 1

Answer:

hope my answer helps you...... ...

Answer 2

Given:

• Height of tower = 5 metres

To find:

• Velocity with which the ball strikes the ground ?

Calculation:

The ball experiences a constant gravitational acceleration of 9.8 m/s² after it is dropped from the tower.

Also, the initial velocity is zero.

So, we can apply the EQUATIONS OF KINEMATICS:

${v}^{2} = {u}^{2} + 2as$

$\implies \: {v}^{2} = {u}^{2} + 2gh$

$\implies \: {v}^{2} = {0}^{2} + 2(10)(5)$

$\implies \: {v}^{2} = 100$

$\implies \: v = \sqrt{100}$

$\implies \: v = 10 \: m {s}^{ - 1}$

So, the ball reaches ground with 10 m/s velocity.