A ball is dropped from a tower with a speed of 20 metre per second. How much time will it take to strike the ground?
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Secondary School Physics 13 points
A body dropped from the top of a tower acquires a velocity of 20m/s on reaching the ground. Calculate the height of the tower.
Ask for details Follow Report by Nikhilsinghai7733 14.05.2018
U = 0 G = 10m/s²
V = 20/s
V = u+gt
20 = 0 + 10t
t = 2s
ht = ut+1/2gt²
= 0 × 2 + 1/2 × 10 × 10 × 2 =
l
Answer:
The height of the tower will be 20.41 m.
Explanation:
Given that,
Velocity v = 20 m/s
Using equation of motion
v2-u^2=2as
Here, u = initial velocity
v= final velocity
g = acceleration due to gravity
s = height of the tower
The height of the tower will be
20^{2}-0=2\times9.8\times s
s= \dfrac{400}{2\times9.8}
s= 20.41\ m
Hence, The height of the tower will be 20.41
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