A ball is dropped from cliff of a tower of height of 40 m what will be its velocity after falling 20 m
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since ball is dropped its initial velocity is 0 i.e. u = 0 m/s²
s = 40 - 20 = 20 m
a = g = 10 m/s²
we know that
v²= u² + 2as
v²= 0 + 2(20)(10)
v² = 400
v =
v = 20
s = 40 - 20 = 20 m
a = g = 10 m/s²
we know that
v²= u² + 2as
v²= 0 + 2(20)(10)
v² = 400
v =
v = 20
NOOBSCIENCESTUDENT:
u should mention value of g.. n if this question is from any enterance booklet then they mostly take g= 10
happy
Ya
Then what will be the velocity of ball at the time of hitting the ground
Plz give me answer
take displacement as 40 you will get answer lol
so v² = 0 + 2(10)(40)
v² = (2)(100)(4)
v = √2 (100)(4)
v = 20√2
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