a ball is dropped from height h. after 1 second another all is dropped from same point. what is the distance between them after 3 seconds from when the first ball dropped?
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Given :-
A ball is dropped from height h. after 1 second another all is dropped from same point.
To Find :-
What is the distance between them after 3 seconds from when the first ball dropped?
Solution :-
We know that
s = ut + 1/2 at²
s = 0(3) + 1/2 × 10 × (3)²
s = 0 + 5 × 9
s = 45 m
Now
New time = 3 - 1 = 2 sec
s = ut + 1/2 at²
s = (0)(2) + 1/2 × (10) × (2)²
s = 0 + 5 × 4
s = 20 m
Now
Distance between them = 45 - 20 = 25 m
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