a ball is dropped from height H. find the time to reach ground
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h=ut+1/2gt^2
here u=0
h=1/2gt^2
2gt^2=1/h
t=root 1/2gth.
Answered by
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Answer:h= ut + 1/2 at^2
Since the ball is dropped, u= 0 m/s and is in freefall so a=g=10
Therefore h=1/2 * 10*t^2
h= 5t^2
t= √(h÷5)
Explanation:
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