a ball is dropped from height have on a horizontal floor. if it loses 60% of its energy on hitting the floor then height upto which it will rise after first renounce is
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Secondary SchoolPhysics 8 points
A ball is dropped from height h on a horizontal floor . If it loses 60% of its energy in hitting the floor then height upto which it will rise after first rebounce is
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Ask for details FollowReport by Ha3zahma2henbhan 11.04.2017
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The velocity of ball just before hitting the floor is sqrt(2gh) and its kinetic energy will be 1/2mu^2=mgh.
after hitting it loses 60% of its energy or we say it possess only 40% of its initial energy .
its energy after hitting the floor is 40/100(mgh)
after reaching its maximum height h' it will lose all its kinetic energy and will possess only potential energy which is mgh'.
therefore law of conservation of energy says that
mgh'=40/100(mgh)
h'=0.4h
What is your question?
1
Secondary SchoolPhysics 8 points
A ball is dropped from height h on a horizontal floor . If it loses 60% of its energy in hitting the floor then height upto which it will rise after first rebounce is
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Ask for details FollowReport by Ha3zahma2henbhan 11.04.2017
Answers
Brainly User
The velocity of ball just before hitting the floor is sqrt(2gh) and its kinetic energy will be 1/2mu^2=mgh.
after hitting it loses 60% of its energy or we say it possess only 40% of its initial energy .
its energy after hitting the floor is 40/100(mgh)
after reaching its maximum height h' it will lose all its kinetic energy and will possess only potential energy which is mgh'.
therefore law of conservation of energy says that
mgh'=40/100(mgh)
h'=0.4h
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