Question

. A ball is dropped from height of 45 m.
Then what is the distance covered in last 0.6 sec of
its motion?​

Answer 1

Answer:

16.07m approx 16m

Explanation:

find the total time

t=√2h/g=3.03sec

distance traveled before last 0.6 second i.e in 2.43 seconds

0.5gt²=28.97m

therefore distance in last 0.6 second = ⁴

45-28.97

=16.07m

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