A ball is dropped from height such that it strikes the ground with speed 20 metre per second and rebounds upward with speed 10 metre per second if ball remained in contact with the surface for 0.5 second then find average acceleration of the Ball during contact
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Answer:
Acceleration,a=-60m/s^2
Explanation:
Initial velocity =20m/s
Final velocity =-10m/s(opposite direction)
t=0.5s
By the formula,
-10=20+0.5a
-10-20=0.5a
-30/0.5=a
a=-60m/s^2
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