Question

A ball is dropped from rest from a tower of height 5m. As a result of the wind it lands at a distance om
from the bottom of the tower as shown. Assuming no air resistance but that the wind gives the ball a
constant horizontal velocity v. Find value of v in m/s.
5 m
landing
point
6 m​

Answer 1

Answer:

10 m/s.

Explanation:

Since, the ball is dropped from the top of the tower which is 5 meter in height and initially the ball was at rest so the initial velocity u =0 while the final velocity v we have to find out.

So, we know that v^2 = u^2 + 2gH where H is the height of the tower.

So, substituting the values on the given equations from the question we will get that v^2 =2gH or v=√(2*10*5) which on solving we will get the value of velocity v to be 10 m/s.