A ball is dropped from rest from the top of a 75 m height tower. What is the velocity of the ball 1.6s before it reaches the ground
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Height and Velocity Functions
Ascertain the height from which the object fell. Multiply the height by 2, and divide the result by the object's acceleration due to gravity. If the object fell from 5 m, the equation would look like this: (2*5 m)/(9.8 m/s^2) =1.02 s^2
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