A ball is dropped from rest. The acceleration due to gravity is 10m s -2 and the time it takes for the ball to reach the ground is 5 seconds. What was the velocity of the ball just before it hit the ground?
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Answer:
50m/s
explanation :
the ball was initially at rest. therefore, u = 0 m/s.
given, a = g = 10m/s
and t = 5s.
therefore, by using the relation v = u + at, we can find the velocity (v) of the ball just before it hits the ground.
v = 0 - (10×5)
v = -50m/s.
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Answer:
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