Question

a ball is dropped from rhe height of 98 m . fine the velocity nd time​

Answer 1

Answer:

43.83 m/s, 4.47 s (approx.)

Explanation:

Given:

Initial velocity (u) = 0 m/s  (as it was dropped from rest)

Acceleration (a) = g = 9.8 m/s²

Displacement (s) = 98 m

To find:

Final velocity (v)

Time (t)

Method to Find:

v² = u² + 2as

⇒ v² = 0 + (2 * 9.8 * 98)

⇒ v² = 1920.8

⇒ v = √1920.8 ≈ 43.83 m/s

v = u + at

⇒ 43.83 = 0 + 9.8t

⇒ t = 43.83/9.8

⇒ t ≈ 4.47 seconds

Hence, the final velocity and time were approximately 43.83 m/s and 4.47 seconds