Question

A ball is dropped from roof of a tower of
height h. The total distance coverd by it in
the last sec of its motion is equal to the
distance covered by it in first three second.
What the value of h? (g=10m/s)
MUTHDIASITE​

Answer 1

Answer:

10h

Explanation:

beacuse it gravity will multiply with h then it will give 10h

Answer 2

Answer:

A ball is dropped from the roof of a tower of height h.The total distance covered by it in the last second of its motion is equal to the distance covered by it in first three seconds.The value of h is

ans is ....

(g=10m/s2)

Explanation:

The distance covered in first 3 second

s=12gt2

=12×10×32

=45

If the ball takes 'n' second to fall to ground . The distance covered in nth second

sn=u+g2(2n−1)

=0+102(2n−1)

=10n−5

Therefore 45=10n−5

n=5

Therefore h=12gt2

=12×10×25

=125m

Hence a is the correct answer.

it helps you to find the question