A ball is dropped from some height and after 6second another ball is dropped from same height with initial speed v .They meet after 18 sec .What is the value of v
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Distance of 1st ball= S= 1/2 x 10 x 18
= 1620
Distance of 2nd ball = S' = ut + 1/2gt²
1620 = 12u + 5 x 144
u = 135 - 60
= 75 m/s
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