a ball is dropped from the height of 20m calculate the time taken by the ball to reach the ground , the velocity with which the ball strikes the ground . given: a=10m/s sq
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Answer:
2sec
Explanation:
v^2 = u^2+2as
v= √{2#10#20). ( u=0)
= 20m/s
now, v=u+ at
20=O+ 10 # t
t= 20/10sec
=2 sec
v= final velocity at the time of strike
u=initial velocity just before the ball is drop so means it is in hand so O m/s
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