A ball is dropped from the leaning tower of Pisa, at a height of 50m from the ground. The ball is dropped
from rest and falls freely under gravity. How long will it be before the ball hits the ground?
Answers
Answered by
3
Answer:
75 m
is the answer
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Answered by
1
Answer:
Consider the motion of ball from A to B.
B→ just above the sand ( just to penetrate)
u=0,a=9.8 m/s
2
,s=5 m
The distance covered by the ball is:
S=ut+
2
1
at
2
⇒5=0+
2
1
(9.8)t
2
⇒t
2
=
4.9
5
=1.02
⇒t=1.01.
∴ velocity at B,v=u+at=9.8×1.01(u=0)=9.89 m/s.
From motion of ball in sand
u
1
=9.89 m/s,v
1
=0,a=?,s=10 cm=0.1 m
a=
2s
v
1
2
−u
1
2
=
2×0.1
0−(9.89)
2
=−490 m/s
2
The retardation in sand is 490 m/s
2
.
Same as above
Explanation:
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