A ball is dropped from the roof of a building 10 metre high calculate the time of fall and the speed with which it hits the ground take g= 10 M per second square
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We know that h=10 metre
Time of fall = (√2hg)/g
Final velocity= √2hg
[Equations of motion under gravity since the body is freely falling initial velocity is considered to be Zero]
Time of fall = [√(2*10*10)]/10 = 10√2/10 = √2 sec = 1.414 sec(approx.)
Final Velocity = √(2*10*10) = √200 = 10√2 m/sec = 14.142m/sec(approx.)
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Time of fall = (√2hg)/g
Final velocity= √2hg
[Equations of motion under gravity since the body is freely falling initial velocity is considered to be Zero]
Time of fall = [√(2*10*10)]/10 = 10√2/10 = √2 sec = 1.414 sec(approx.)
Final Velocity = √(2*10*10) = √200 = 10√2 m/sec = 14.142m/sec(approx.)
I hope this answer helps you and if you like it please mark it brainliest. :D
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