Math, asked by tejaswigurrapu05tg, 1 day ago

A ball is dropped from the roof of a tall building and simultaneously another ball is through horizontally with some roof
which ball lands first? explain your answer​

Answers

Answered by clementcherian
0

Answer:

Step-by-step explanation:

Let ℎ

h

be the height of the tall building.

For dropped ball:

Let

t_1

be the time taken by the dropped ball to reach the ground.

Initial velocity , u=0, Acceleration , a= + g

Distance travelled, s=h, Time of travel , =1

t

=

t

1

From the equation of motion, =+122

s

=

u

t

+

1

2

a

t

2

we can write

ℎ=0×1+12××21⇒ℎ=1221⇒21=2ℎ

h

=

0

×

t

1

+

1

2

×

g

×

t

1

2

h

=

1

2

g

t

1

2

t

1

2

=

2

h

g

(or) 1=2ℎ‾‾‾√

t

1

=

2

h

g

____(1)

For horizontally projected ball:

If the ball is thrown horizontally then its initial velocity along vertical direction is zero and in this case let

t_2

be the time taken by the ball to reach the ground.

Again from the equation of motion,

=+122

s

=

u

t

+

1

2

a

t

2

we write,

⇒ℎ=0×2+12×22

h

=

0

×

t

2

+

1

2

g

×

t

2

2

⇒ℎ=1222

h

=

1

2

g

t

2

2

,

⇒22=2ℎ

t

2

2

=

2

h

g

or2=2ℎ‾‾‾√

t

2

=

2

h

g

______(2)

From equation s (1) and (2) 1=2

t

1

=

t

2

i.e., both the balls reach the ground in the same time.

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