A ball is dropped from the top of 20 meter. If it's velocity increases with an acceleration of 10 m/s² then what speed will the ball hit the ground ? How much time will it take to hit the ground ?
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Answer:
2 sec
Explanation:
s=ut + 1/2 at^2
20= 0 + 1/2 *10*t^2
t^2 = 20/5= 4
hence t= 2 sec
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