a ball is dropped from the top of 80m high tower.if after 2 sec of fall the gravity disappers, then time taken to reach ground since the gravity disapperd
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Answer:
S=1/2gt²
=2g=2×10=20m
Remaining distance= 80-20 =60m
Velocity after 1 secs= gt=20m/s
Gravity dissappers i.e.,
The body falls with constant velocity
V= 20m/s
Time taken= 60/20= 3secs
Total time = 5secs
Explanation:
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