Question

a ball is dropped from the top of 80m high tower.if after 2 sec of fall the gravity disappers, then time taken to reach ground since the gravity disapperd

Answer 1

Answer:

S=1/2gt²

=2g=2×10=20m

Remaining distance= 80-20 =60m

Velocity after 1 secs= gt=20m/s

Gravity dissappers i.e.,

The body falls with constant velocity

V= 20m/s

Time taken= 60/20= 3secs

Total time = 5secs

Explanation: