Question

A ball is dropped from the top of a building. After 2 seconds, it hit the ground. The ball accelerated at 9.8m/s/s. What is the final velocity of the dropped ball?

Answer 1

Answer:

v = u + gt

= 0 + 9.8 * 2

= 19.6 m/s

the final velocity = 19.6

hope it helps

Answer 2

QUESTION :-

A ball is dropped from the top of a building. After 2 seconds, it hit the ground. The ball accelerated at 9.8m/s². What is the final velocity of the dropped ball?

Given :-

• a = 9.8m/s²

• t = 2sec

• u = 0m/s

Find :-

• v = ?

SOLUTION :-

As We know that,

==> a = (v-u) /t

==> 9.8 = (v -0)/2

==> .°. 9.8×2= v

==> .°. v = 19.6m/s

Hence, the final velocity is 19.6m/s.