Question

A ball is dropped from the top of a building. Assume the initial velocity (V1) is 0 from a distance of 44.1 meter. Find the final velocity (Vf) of a ball.​

Answer 1

Answer:

Initial Velocity (u) = 0 m/s

Height (h) = 44.1 m

Acceleration due to gravity (g) = 9.8 m/s²

∴ v² = u² + 2gh

= v² = 2*9.8*44.1

= v² = 864.36

= v = 29.4 m/s

I hope this helps.