A ball is dropped from the top of a building. Assume the initial velocity (V1) is 0 from a distance of 44.1 meter. Find the final velocity (Vf) of a ball.
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Answer:
Initial Velocity (u) = 0 m/s
Height (h) = 44.1 m
Acceleration due to gravity (g) = 9.8 m/s²
∴ v² = u² + 2gh
= v² = 2*9.8*44.1
= v² = 864.36
= v = 29.4 m/s
I hope this helps.
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