Question

A ball is dropped from the top of a building,The ball takes 0.5s to fall past the 3m height of a window some distance from the top of the building If the speed of the ball at the top and the bottom of the window are u and v respectively,then find a relation between u and v

Answer 1

Answer:

v+u=12

Explanation:

v=u+at

V=u+a(0.5)

Also v^2=u^2+2as

(v+u)(v-u)=2×2(v-u)×3

V+u=12