Question

A ball is dropped from the top of a building. The ball takes 0.5s to fall past the window of 3m in length at certain distance from the top of the building. (g=10m/s2) how fast was the ball going as it passed the bottom of the window?

Answer 1

Answer:

8.45m/s

Explanation:

t=0.5

s=3

a=9.8

v=?

s=vt-1/2at^2

3=0.5v-4.9*0.5^2

3=0.5v-1.225

4.225=0.5v

v=8.45m/s