Question

A ball is dropped from the top of a building. The ball takes 0.5 seconds to fall past the 3m Height of a window some distance from the top of the building. If the speed of the ball at the top and bottom of the window is given by vT and vB respectively, then (g = 9.8m/(sec*sec))
A) vT+vB = 12 m/s
B) vT-vB = 4.9 m/s
C) vBvT = 1m/s
D) vB/vT = 1m/s

Answer 1

Answer:

B) vT-vB = 4.9 m/s

Explanation:

B) vT-vB = 4.9 m/s