Physics, asked by roygunjan07, 5 months ago

a ball is dropped from the top of a building . the ball takes 1/4 s to fall past 12 m length of a sign board some distance from the top of the buildings . If the velocity of the ball at the top and at the bottom of thr board are v1 and v2 then 1) v1+v2= 96ms-1 2) v1-v2 =9.8ms-1 3) v1v2 = 1m2s-2 4) v1/v2 =1

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Answered by saif9671
0

Answer:

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