A ball is dropped from the top of a height 80m at the same time another ball is projected horizontally from the tower . find the time taken by both the balls to reach the ground
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Answered by
20
Both the balls will take same time to reach the tower.
![t = \sqrt{ \frac{2 \times h}{g} } t = \sqrt{ \frac{2 \times h}{g} }](https://tex.z-dn.net/?f=t+%3D++%5Csqrt%7B+%5Cfrac%7B2+%5Ctimes+h%7D%7Bg%7D+%7D+)
Using the above formula
![t = \sqrt{ \frac{2 \times 80}{10} } t = \sqrt{ \frac{2 \times 80}{10} }](https://tex.z-dn.net/?f=t+%3D++%5Csqrt%7B+%5Cfrac%7B2+%5Ctimes+80%7D%7B10%7D+%7D+)
Therefore time taken is equal to 4 seconds
Using the above formula
Therefore time taken is equal to 4 seconds
Answered by
17
Both the balls will take the same time to reach the ground as the time of fall is decided by the velocity along the y acis of motion which is zero in both the cases.
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