Question

A ball is dropped from the top of a high tower.
Distance travelled by the ball in 2nd second of its
motion is (g = 10 m/s?]
(1) 5 m
(2) 15 m
(3) 20 m
(4) 25 m​

Answer 1

Answer:

distance traveled by the ball in 2 second is 20 m watch the attachment

Answer 2

ANSWER:

The distance traveled by the ball in 2 s will be 20 m from the top of the high tower.

EXPLANATION:

The dropping of ball from high tower makes the ball to experience a free fall. So the motion of the ball falling downward will have uniform acceleration and that acceleration will also be equal to the acceleration to gravity. As it is a free fall so the direction of acceleration exerted on the ball will be equal to the direction of acceleration due to gravity. So as the free fall indicates the uniform acceleration, so we can use any one of the equations of motion to determine the distance travelled by the ball in 2s. The three equations of motion are

v=u+a t

$s=u t+\frac{1}{2}a t^{2}$

$2 a s=v^{2} -u^{2}$

As we known the time at which the distance is to be measured and the acceleration and initial velocity of the ball will be 10 m/s2 and zero, respectively, so we can use the second equation of motion to determine the distance of the ball in 2s of its motion.

$s=u t+\frac{1}{2} a t^{2}$

$s=(0 * 2)+\left(\frac{1}{2} * 10 * 2 * 2\right)$

s=0+20  

s=20 m

Thus the distance travelled by the ball in 2 s will be 20 m from the top of the high tower.